x^2+10x-816=0

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Solution for x^2+10x-816=0 equation: 



x^2+10x-816=0

a = 1; b = 10; c = -816;
Δ = b2-4ac
Δ = 102-4·1·(-816)
Δ = 3364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3364}=58$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-58}{2*1}=\frac{-68}{2}
=-34
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+58}{2*1}=\frac{48}{2}
=24
$

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